Physics · Class 12 · Dual Nature of Matter and Radiation

Dual Nature of Matter and Radiation for JEE

Everything you need for this topic on one page: the ideas, the formulas, the traps, and free lectures that explain it well.

Last updated: 26 October 2026

Direct answer

Photoelectric effect, photons, work function, stopping potential and de Broglie waves.

Photoelectric effect, photons, work function, stopping potential and de Broglie waves.

Key ideas

Dual Nature of Matter and Radiation: what you must understand

  • Light behaves as photons with energy hf
  • Photoemission needs f above the threshold frequency; intensity changes only the current
  • Stopping potential depends on frequency, not intensity
  • Moving particles have a wavelength λ = h/p
Formula sheet

Must-know formulas for Dual Nature of Matter and Radiation

  • E = hf = hc/λ; hc ≈ 1240 eV·nm
  • K_max = hf − φ = eV₀
  • de Broglie λ = h/p = h/√(2mK)
  • Electron accelerated through V: λ ≈ 1.227/√V nm
Print

One-page formula sheet

Printable Dual Nature of Matter and Radiation formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.

Avoid

Common mistakes students make

  • Thinking higher intensity increases K_max
  • Unit mix-ups between eV and joules
  • Using λ = h/mv for photons
For the exam

How this topic is asked in JEE

Appears in almost every JEE Main shift. Modern Physics is among the most scoring parts of JEE Main. Use hc = 1240 eV·nm to save time.

NCERT map

Where Dual Nature of Matter and Radiation is in NCERT

Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.

ClassBookChapterSections JEE asks from
Class 12Physics Part IIDual Nature of Radiation and MatterPhotoelectric Effect; Einstein's Photoelectric Equation: Energy Quantum of Radiation; Particle Nature of Light: The Photon; Wave Nature of Matter
JEE Advanced level

A JEE Advanced-level example on Dual Nature of Matter and Radiation

Question. Light of wavelength 200 nm is incident on a metal surface having work function 4.2 eV. The photoelectrons emitted with maximum kinetic energy are then accelerated through an additional potential difference V. If the de Broglie wavelength of these accelerated electrons is 0.1 nm, find the value of V. (Take h = 6.63 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, mass of electron = 9.1 × 10⁻³¹ kg)

Show solution
  1. Energy of incident photon: E = hc/λ = (1240 eV·nm)/(200 nm) = 6.2 eV
  2. Maximum KE of photoelectrons: KE_max = E − φ = 6.2 − 4.2 = 2.0 eV
  3. After acceleration through V, total KE = (2.0 + V) eV
  4. Using de Broglie relation: λ_dB = h/√(2m·KE), so 0.1 nm = h/√(2m·KE_total)
  5. Solving: KE_total = h²/(2m·λ²) = (6.63 × 10⁻³⁴)²/(2 × 9.1 × 10⁻³¹ × 10⁻²⁰) ≈ 150 eV
  6. Therefore V = KE_total − KE_max = 150 − 2 = 148 V ≈ 150 V

Answer: V ≈ 148 to 150 V

This example was solved twice independently and both solutions agree.

Free lectures

Best free lectures for Dual Nature of Matter and Radiation

Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.

FAQs

Frequently asked questions

Is Dual Nature of Matter and Radiation important for JEE Main 2027?

Appears in almost every JEE Main shift. It is part of the official 'Dual Nature of Matter and Radiation' unit in the JEE Main 2027 syllabus.

What are the most important formulas in Dual Nature of Matter and Radiation?

E = hf = hc/λ; hc ≈ 1240 eV·nm; K_max = hf − φ = eV₀; de Broglie λ = h/p = h/√(2mK).

How should I study Dual Nature of Matter and Radiation for JEE?

Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Modern Physics is among the most scoring parts of JEE Main. Use hc = 1240 eV·nm to save time.

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