Direct answer

Coulomb's law, electric field, Gauss's law, electric potential, potential energy and dipoles.

Coulomb's law, electric field, Gauss's law, electric potential, potential energy and dipoles. One of the highest-frequency JEE chapters.

Key ideas

Electrostatics (Electric Charges and Fields, Potential): what you must understand

  • Field lines start on + and end on − charges
  • Gauss's law: flux = q_enclosed / ε₀
  • Field inside a conductor is zero; charge sits on the surface
  • E = −dV/dr
Formula sheet

Must-know formulas for Electrostatics (Electric Charges and Fields, Potential)

  • F = kq₁q₂/r², k = 1/(4πε₀)
  • Infinite line: E = λ/(2πε₀r); infinite sheet: σ/(2ε₀)
  • Point charge: V = kq/r; dipole on axis: E = 2kp/r³
  • Potential energy U = kq₁q₂/r
Print

One-page formula sheet

Printable Electrostatics (Electric Charges and Fields, Potential) formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.

Avoid

Common mistakes students make

  • Adding fields as scalars
  • Using Gauss's law where there is no symmetry
  • Forgetting that potential is a scalar and can be added directly
For the exam

How this topic is asked in JEE

Appears in almost every JEE Main shift. Expect 1–2 questions. Gauss's law and potential due to systems of charges are very common.

NCERT map

Where Electrostatics (Electric Charges and Fields, Potential) is in NCERT

Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.

ClassBookChapterSections JEE asks from
Class 12Physics Part IElectric Charges and FieldsCoulomb's Law; Electric Field; Electric Field Lines; Electric Dipole; Gauss's Law
Class 12Physics Part IElectrostatic Potential and CapacitanceElectric Potential; Potential due to an Electric Dipole; Equipotential Surfaces; Potential Energy in an External Field
JEE Advanced level

A JEE Advanced-level example on Electrostatics (Electric Charges and Fields, Potential)

Question. An electric dipole with dipole moment p = 2 × 10⁻⁶ C·m is placed at the origin with its axis along the x-axis (positive charge on the +x side). A point charge q = +1 μC is initially at point A located at (0, 3 cm) and is moved to point B at (4 cm, 0). Find the work done by the electric field of the dipole on the point charge.

Show solution
  1. Potential due to dipole: V = kp cos θ / r², where θ is angle from dipole axis
  2. At point A: r = 0.03 m, θ = 90° (equatorial position), so V_A = kp cos 90° / r² = 0
  3. At point B: r = 0.04 m, θ = 0° (axial position), so V_B = (9 × 10⁹ × 2 × 10⁻⁶) / (0.04)² = 1.125 × 10⁷ V
  4. Work done by electric field: W = q(V_A − V_B) = 10⁻⁶ × (0 − 1.125 × 10⁷)
  5. W = −11.25 J (negative sign means work is done against the field)

Answer: W = −11.25 J

This example was solved twice independently and both solutions agree.

Free lectures

Best free lectures for Electrostatics (Electric Charges and Fields, Potential)

Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.

FAQs

Frequently asked questions

Is Electrostatics (Electric Charges and Fields, Potential) important for JEE Main 2027?

Appears in almost every JEE Main shift. It is part of the official 'Electrostatics' unit in the JEE Main 2027 syllabus.

What are the most important formulas in Electrostatics (Electric Charges and Fields, Potential)?

F = kq₁q₂/r², k = 1/(4πε₀); Infinite line: E = λ/(2πε₀r); infinite sheet: σ/(2ε₀); Point charge: V = kq/r; dipole on axis: E = 2kp/r³.

How should I study Electrostatics (Electric Charges and Fields, Potential) for JEE?

Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Expect 1–2 questions. Gauss's law and potential due to systems of charges are very common.

WA✎
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