Nucleophilic addition, aldol and Cannizzaro reactions, oxidation and reduction, and tests for aldehydes and ketones.
Nucleophilic addition, aldol and Cannizzaro reactions, oxidation and reduction, and tests for aldehydes and ketones.
Everything you need for this topic on one page: the ideas, the formulas, the traps, and free lectures that explain it well.
Last updated: 26 October 2026
Nucleophilic addition, aldol and Cannizzaro reactions, oxidation and reduction, and tests for aldehydes and ketones.
Printable Aldehydes and Ketones formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.
Appears in almost every JEE Main shift. Very frequent. Named reactions here are NCERT favourites.
Prerequisites: General Organic Chemistry (GOC).
Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.
| Class | Book | Chapter | Sections JEE asks from |
|---|---|---|---|
| Class 12 | Chemistry Part II | Aldehydes, Ketones and Carboxylic Acids | Nucleophilic addition reactions; Aldol condensation; Cannizzaro reaction; Oxidation of aldehydes and ketones; Reduction of aldehydes and ketones |
Question. Compound X (molecular formula C₈H₈O) gives a positive iodoform test but does not reduce Tollens' reagent. When X is treated with benzaldehyde in dilute NaOH, compound Y (C₁₅H₁₂O) is formed. However, benzaldehyde alone when treated with concentrated NaOH gives an equimolar mixture of P and Q. (a) Identify X and Y. (b) Identify P and Q and name the reaction. (c) Explain why X does not undergo the same reaction as benzaldehyde with concentrated NaOH.
Answer: (a) X = Acetophenone (C₆H₅COCH₃), Y = Benzalacetophenone/Chalcone (C₆H₅CH=CHCOC₆H₅). (b) P = Sodium benzoate, Q = Benzyl alcohol; Cannizzaro reaction. (c) Acetophenone has α-hydrogens so it undergoes aldol condensation instead of Cannizzaro reaction.
This example was solved twice independently and both solutions agree.
Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.
Appears in almost every JEE Main shift. It is part of the official 'Organic Compounds Containing Oxygen' unit in the JEE Main 2027 syllabus.
Clemmensen: C=O → CH₂ (Zn-Hg/HCl); Wolff–Kishner: C=O → CH₂ (N₂H₄/KOH); Cannizzaro: 2 HCHO → HCOO⁻ + CH₃OH.
Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Very frequent. Named reactions here are NCERT favourites.