⚖️ Stoichiometry & Limiting Reagent Calculator
Mole ConceptWhat's happening? 2A + B → 2C. Compare moles/coefficient ratios. The smaller ratio is the limiting reagent. It determines how much product forms.
Stoichiometry: 8-12 questions every year. Highest weightage.
JEE tests limiting reagent, % yield, molarity, mixed problems.
Key formulas
Stoichiometry & Limiting Reagent Formulas
Limiting reagent
n_actual / coefficient (smallest = limiting)
Divide moles by coefficient
% yield
% = (actual/theoretical) x 100
Actual from experiment
Molarity
M = n/V
moles per liter
Dilution
M1V1 = M2V2
Moles conserved
Step-by-step problem solving
How to solve chemistry problems in JEE
- Balance the equation
- Convert to moles
- Divide by coefficients, find smallest
- Calculate product from limiting reagent
Common JEE mistakes
What students get wrong
Not balancing
Always balance first
Actual vs stoichiometric
Divide actual moles by coefficient
Wrong volume units
Molarity needs liters
Gas volume to moles
STP: 1 mol = 22.4 L
FAQs
Stoichiometry & Limiting Reagent Questions
Find limiting reagent?
Divide moles by coefficient. Smallest = limiting
Theoretical yield?
Max product from limiting reagent, 100% conversion
Multi-step stoichiometry?
Chain: moles A -> B -> C using coefficients
Molarity vs molality?
M = mol/L solution, m = mol/kg solvent