Pressure and temperature explained by molecular motion: rms speed, degrees of freedom, equipartition and mean free path.
Pressure and temperature explained by molecular motion: rms speed, degrees of freedom, equipartition and mean free path.
Everything you need for this topic on one page: the ideas, the formulas, the traps, and free lectures that explain it well.
Last updated: 26 October 2026
Pressure and temperature explained by molecular motion: rms speed, degrees of freedom, equipartition and mean free path.
Printable Kinetic Theory of Gases formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.
Appears regularly; quick marks. Short, scoring chapter. One question is common.
Prerequisites: Thermodynamics.
Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.
| Class | Book | Chapter | Sections JEE asks from |
|---|---|---|---|
| Class 11 | Physics Part II | Kinetic Theory | Molecular nature of matter; Kinetic theory of an ideal gas; Law of equipartition of energy; Mean free path |
Question. A vessel contains a mixture of helium (He, monatomic) and nitrogen (N₂, diatomic) at 300 K. The partial pressures are P_He = 2 atm and P_N₂ = 3 atm. (a) Find the ratio of rms speeds v_He : v_N₂. (b) Find the ratio of total internal energy U_He : U_N₂ in the vessel. (c) If the mean free path of N₂ is 2 × 10⁻⁷ m and its collision diameter is 3 × 10⁻¹⁰ m, calculate the number density of N₂ molecules. (M_He = 4 g/mol, M_N₂ = 28 g/mol)
Answer: (a) √7 or approximately 2.65, (b) 2/5 or 0.4, (c) 1.25 × 10²⁵ molecules/m³
This example was solved twice independently and both solutions agree.
Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.
Appears regularly; quick marks. It is part of the official 'Kinetic Theory of Gases' unit in the JEE Main 2027 syllabus.
P = ⅓ρv_rms²; v_rms = √(3RT/M), v_avg = √(8RT/πM), v_mp = √(2RT/M); Cᵥ = fR/2, γ = 1 + 2/f.
Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Short, scoring chapter. One question is common.