Maths · Class 11 · Co-ordinate Geometry

Circles for JEE

Everything you need for this topic on one page: the ideas, the formulas, the traps, and free lectures that explain it well.

Last updated: 26 October 2026

Direct answer

Equation of a circle, tangents and normals, chord of contact, family of circles and position of lines and circles.

Equation of a circle, tangents and normals, chord of contact, family of circles and position of lines and circles.

Key ideas

Circles: what you must understand

  • General form x² + y² + 2gx + 2fy + c = 0, centre (−g, −f)
  • Line is tangent if distance from centre = radius
  • Two circles: compare distance between centres with radii
  • Radical axis: S₁ − S₂ = 0
Formula sheet

Must-know formulas for Circles

  • Radius r = √(g² + f² − c)
  • Tangent at (x₁, y₁): T = 0
  • Length of tangent = √S₁
  • Orthogonal circles: 2g₁g₂ + 2f₁f₂ = c₁ + c₂
Print

One-page formula sheet

Printable Circles formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.

Avoid

Common mistakes students make

  • Sign of centre coordinates
  • Forgetting the condition r² > 0
  • Wrong formula for common tangents count
For the exam

How this topic is asked in JEE

Appears frequently. Regular source of questions. Learn the T = 0 and S₁ shortcuts.

Prerequisites: Straight Lines.

NCERT map

Where Circles is in NCERT

Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.

ClassBookChapterSections JEE asks from
Class 11MathematicsConic SectionsCircle; Equation of a Circle; Position of a Point with Respect to a Circle; Tangent to a Circle
JEE Advanced level

A JEE Advanced-level example on Circles

Question. A circle passes through the point (2, 3) and touches the line x + y = 1 at the point (1, 0). Find the equation of the circle.

Show solution
  1. The circle touches line x + y = 1 at (1, 0), so the center lies on the normal to this line at (1, 0). The normal has slope 1 (perpendicular to slope -1), giving the line y = x − 1. So center = (h, h − 1).
  2. Radius = distance from center to (1, 0) = √[(h − 1)² + (h − 1)²] = |h − 1|√2
  3. Since (2, 3) lies on the circle: (2 − h)² + (3 − (h − 1))² = 2(h − 1)²
  4. Expanding: (2 − h)² + (4 − h)² = 2(h − 1)² gives 2h² − 12h + 20 = 2h² − 4h + 2, so h = 9/4
  5. Center = (9/4, 5/4) and r² = 2(5/4)² = 25/8

Answer: (x − 9/4)² + (y − 5/4)² = 25/8, or equivalently 2x² + 2y² − 9x − 5y + 7 = 0

This example was solved twice independently and both solutions agree.

Free lectures

Best free lectures for Circles

Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.

Practise

Where to practise for free

FAQs

Frequently asked questions

Is Circles important for JEE Main 2027?

Appears frequently. It is part of the official 'Co-ordinate Geometry' unit in the JEE Main 2027 syllabus.

What are the most important formulas in Circles?

Radius r = √(g² + f² − c); Tangent at (x₁, y₁): T = 0; Length of tangent = √S₁.

How should I study Circles for JEE?

Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Regular source of questions. Learn the T = 0 and S₁ shortcuts.

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