Chemistry · Class 11 · Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure for JEE

Everything you need for this topic on one page: the ideas, the formulas, the traps, and free lectures that explain it well.

Last updated: 26 October 2026

Direct answer

Ionic and covalent bonds, VSEPR shapes, hybridisation, bond parameters, resonance, MOT, dipole moment and hydrogen bonding.

Key ideas

Chemical Bonding and Molecular Structure: what you must understand

Hybridisation from steric number: 2 sp, 3 sp², 4 sp³, 5 sp³d, 6 sp³d²
Lone pairs distort ideal bond angles
MOT bond order = (bonding − antibonding)/2
O₂ is paramagnetic (two unpaired electrons)

Formula sheet

Must-know formulas for Chemical Bonding and Molecular Structure

Steric number = σ bonds + lone pairs on central atom
Bond order = (N_b − N_a)/2
Dipole moment μ = q × d
% ionic character ≈ μ_observed / μ_ionic × 100

One-page formula sheet

Printable Chemical Bonding and Molecular Structure formula sheet: formulas, key ideas and traps on one page. Save it as a PDF for offline revision.

Avoid

Common mistakes students make

Confusing shape with geometry when lone pairs exist
Wrong MOT order for B₂, C₂, N₂ vs O₂, F₂
Ignoring resonance when comparing bond lengths

For the exam

How this topic is asked in JEE

Appears in almost every JEE Main shift. Bonding is tested in almost every shift and also helps organic and inorganic. Do it thoroughly.

Prerequisites: Atomic Structure.

NCERT map

Where Chemical Bonding and Molecular Structure is in NCERT

Chapter names follow the current rationalised NCERT textbooks. Read these sections before solving PYQs.

Class	Book	Chapter	Sections JEE asks from
Class 11	Chemistry Part I	Chemical Bonding and Molecular Structure	VSEPR Theory; Hybridisation; Molecular Orbital Theory; Hydrogen Bonding; Bond Parameters

JEE Advanced level

A JEE Advanced-level example on Chemical Bonding and Molecular Structure

Question. For the molecule XeF4: (a) Determine the hybridisation of the central Xe atom. (b) Predict the electron geometry and molecular shape using VSEPR theory. (c) Is XeF4 polar or non-polar? Explain based on dipole moment. (d) Count the total number of sigma and pi bonds.

Show solution

Count valence electrons: Xe has 8, each F contributes 1 for bonding. Total electron pairs around Xe = (8 + 4)/2 = 6 pairs (4 bonding + 2 lone pairs).
Hybridisation: 6 electron domains require sp³d² hybridisation.
VSEPR: 6 electron domains give octahedral electron geometry. The 2 lone pairs occupy opposite axial positions to minimize repulsion, placing 4 F atoms in a plane. Molecular shape = square planar.
Dipole moment: Square planar geometry is symmetric. The 4 equal Xe-F bond dipoles point in opposite directions and cancel completely. Net dipole moment = 0, so XeF4 is non-polar.
Bond count: Each Xe-F is a single bond (1 sigma bond each). Total = 4 sigma bonds and 0 pi bonds.

Answer: (a) sp³d² (b) Electron geometry: octahedral, Molecular shape: square planar (c) Non-polar (dipole moment = 0 due to symmetric cancellation) (d) 4 sigma bonds, 0 pi bonds

This example was solved twice independently and both solutions agree.

Free lectures

Best free lectures for Chemical Bonding and Molecular Structure

Full-chapter free lectures picked from YouTube search results by views, from established JEE channels (mostly in Hinglish). Use the subtopic list to jump straight to the part you need (timestamps come from each video's own chapter list). Watch one, then solve PYQs the same day.

CHEMICAL BONDING in One Shot: All Concepts & PYQs Covered | JEE Main & Advanced — JEE Wallah, 9:29:34
Jump to a subtopic (32)
- 00:00 Introduction
- 04:43 Topics to be covered
- 10:50 Valence Electron & Lewis Symbol
- 15:55 Bond
- 19:52 Octet Rule
- 50:58 Covalency
- 01:03:25 Existence & Non-Existence
- 01:19:02 Formal Charge
- 01:31:02 Resonance
- 01:55:00 Valence Bond Theory
- 02:09:30 Nature & Phase of Atomic Orbital
- 02:45:08 Valence Shell Electron Pair Repulsion Theory & Order of Repulsive Interaction
- 03:51:55 Hybridisation
- 04:20:43 Drago's Compounds
- 04:27:38 Steric Number Rule
- 04:55:22 % Character
- 05:11:00 Bent's Rule
- 05:22:25 Hybridisation in odd Electron species
- 05:26:50 No of pie Bonds
- 05:45:14 Karishma of % s Character in Bond Angle
- 06:12:02 Bond Angle
- 06:24:40 Dipole Moment
- 06:58:44 MOT
- 07:08:42 Linear Combination of Atomic Orbitals
- 08:20:30 Ionic Bonding
- 08:27:56 Lattice Energy
- 08:32:18 Fajan's Rule
- 08:48:42 Properties of an Ionic compound
- 08:51:50 Intermolecular Force of Attraction
- 09:05:50 Hydration Energy & Hydrogen Bonding
- 09:22:30 Water
- 09:28:15 Thank you
JEE Brief: CHEMICAL BONDING One Shot CHEMISTRY for JEE Main and Advanced | Sakshi Vora — Vora Classes, 6:19:41

Practise

Where to practise for free

10 JEE Main 2026 PYQs on Chemical Bonding and Molecular Structure, with solutions.
Read the chapter in NCERT textbooks (official, free), then solve its NCERT Exemplar (official, free) questions.
Chapter-wise past questions: JEE Main and Advanced PYQs and question bank.
Timed practice tests: NTA Abhyas practice tests (official, free) and our free mock tests.
See it move: interactive simulation.

FAQs

Frequently asked questions

Is Chemical Bonding and Molecular Structure important for JEE Main 2027?

Appears in almost every JEE Main shift. It is part of the official 'Chemical Bonding and Molecular Structure' unit in the JEE Main 2027 syllabus.

What are the most important formulas in Chemical Bonding and Molecular Structure?

Steric number = σ bonds + lone pairs on central atom; Bond order = (N_b − N_a)/2; Dipole moment μ = q × d.

How should I study Chemical Bonding and Molecular Structure for JEE?

Understand the key ideas from NCERT or one full lecture, learn the formula sheet, then solve 25–30 past JEE questions on the topic. Bonding is tested in almost every shift and also helps organic and inorganic. Do it thoroughly.