Physics · JEE Advanced only

Law of Radioactive Decay, Half-life and Mean Life (JEE Advanced)

Not in the JEE Main syllabus, but it is in JEE Advanced. Study time: about 3 to 4 hours for concepts and formula derivations, plus 2 to 3 hours of problem practice. Total around 6 hours spread over 2 to 3 days..

Last updated: 26 October 2026

Direct answer

Radioactive decay is a random process where unstable nuclei spontaneously transform into more stable ones by emitting radiation.

Radioactive decay is a random process where unstable nuclei spontaneously transform into more stable ones by emitting radiation. The law of radioactive decay tells you exactly how the number of undecayed nuclei decreases over time, and half-life and mean life are two ways to measure how fast this happens.

Official syllabus

What the JEE Advanced syllabus says

“Law of radioactive decay; Decay constant; Half-life and mean life”

Source: JEE Advanced 2026 Information Bulletin, Annexure-I. Closest JEE Main topic: Composition and size of nucleus, atomic masses.

JEE Main only covers basic nuclear structure, but Advanced expects you to work with the exponential decay law, calculate activities, and solve problems involving half-life and mean life. You need to be comfortable with the mathematics of exponential functions and their applications to decay chains.

Key ideas

What you must understand

  • Radioactive decay is statistical: you cannot predict when a single nucleus will decay, but you can predict how many will decay in a large sample
  • The decay constant λ represents the probability of decay per unit time for a single nucleus
  • Half-life (T₁/₂) is the time for half the nuclei to decay; mean life (τ) is the average lifetime of a nucleus before it decays
  • Activity (A) is the number of decays per second, measured in Becquerel (1 Bq = 1 decay/s) or Curie
  • After n half-lives, the fraction remaining is (1/2)ⁿ, which is useful for quick calculations
  • The relationship T₁/₂ = τ × ln(2) connects half-life and mean life, so τ is always larger than T₁/₂
Formulas

Formulas and key facts

  • dN/dt = −λN (fundamental decay law)
  • N(t) = N₀ × e^(−λt) (number of undecayed nuclei at time t)
  • A(t) = λN(t) = A₀ × e^(−λt) (activity at time t)
  • T₁/₂ = ln(2)/λ = 0.693/λ (half-life)
  • τ = 1/λ (mean life)
  • T₁/₂ = τ × ln(2) ≈ 0.693τ
  • N(t) = N₀ × (1/2)^(t/T₁/₂) (alternate form using half-life)
  • Number decayed = N₀ − N(t) = N₀(1 − e^(−λt))
Avoid

Common mistakes

  • Confusing half-life and mean life: mean life τ = 1/λ is about 44% larger than half-life T₁/₂ = 0.693/λ
  • Forgetting that activity A = λN, not just N; activity also decays exponentially with the same time constant
  • Using N = N₀/2 after one mean life instead of one half-life; after one mean life, N = N₀/e ≈ 0.37N₀
  • In problems with two decaying species, forgetting that each has its own decay constant and they decay independently
Worked example

A JEE Advanced-level example

Question. A radioactive sample has a half-life of 20 minutes. Find the ratio of the number of nuclei decayed in the first 20 minutes to the number decayed in the next 20 minutes.

Show solution
  1. Let initial number of nuclei = N₀
  2. After first 20 minutes (one half-life): N₁ = N₀/2, so nuclei decayed in first interval = N₀ − N₀/2 = N₀/2
  3. After next 20 minutes (total 40 min = two half-lives): N₂ = N₀/4, so nuclei remaining after 40 min = N₀/4
  4. Nuclei decayed in second interval = N₁ − N₂ = N₀/2 − N₀/4 = N₀/4
  5. Required ratio = (N₀/2)/(N₀/4) = 2

Answer: The ratio is 2:1

Solved twice independently; both solutions agree.

FAQs

Frequently asked questions

Is Law of Radioactive Decay, Half-life and Mean Life in the JEE Main syllabus?

No. It is in the JEE Advanced 2026 syllabus only. The closest JEE Main topic is Composition and size of nucleus, atomic masses.

How long does Law of Radioactive Decay, Half-life and Mean Life take to prepare for JEE Advanced?

About 3 to 4 hours for concepts and formula derivations, plus 2 to 3 hours of problem practice. Total around 6 hours spread over 2 to 3 days., if you already know the related JEE Main topic.

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