JEEM_2025_22Jan_E_Q1 Solution in 2 minutes
Answer-first note: Use conditional probability from the exact original wording; verify whether the source asks ordered draws, unordered draws, or a non-reduced m/n.
Question: Two balls without replacement from 4 white, 6 black. P(first black | second black)=m/n; find m+n.
Source note: JEE Main 2025; reported answer varies across memory-based copies.
Tags: JEE Main 2025, 22 January Evening Shift, Mathematics, Probability, solution available.
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Two balls without replacement from 4 white, 6 black. P(first black | second black)=m/n; find m+n.
Probability should be revised before attempting this problem under time pressure.
Use conditional probability from the exact original wording; verify whether the source asks ordered draws, unordered draws, or a non-reduced m/n.
Compare with official answer key or trusted coaching solution.
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Summary table
| Area | What to do |
|---|---|
| Exam tag | JEE Main 2025 22 January Evening Shift. |
| Subject/topic tag | Mathematics / Probability. |
| Difficulty tag | Moderate to memory-based. |
| Source caution | JEE Main 2025; reported answer varies across memory-based copies.. |
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| Area | What to know |
|---|---|
| If you feel stuck | Shrink the task to one concept, ten questions, or one counselling comparison. Momentum matters more than a perfect plan. |
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JEEM_2025_22Jan_E_Q1 is tagged as Mathematics / Probability.
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