Physics · Kinematics

Projectile Motion Simulator

Adjust the launch speed and angle, watch the cannonball fly, and see exactly how range, max height, and time of flight change in real time.

🚀 Projectile Motion Simulator

Kinematics
What's happening? The cannonball follows a parabolic path. Range = u²sin2θ/g. Try 45° for maximum range. Notice how the velocity components vx and vy change during flight.
Why this matters for JEE

Projectile motion is the most-tested kinematics concept in JEE Main.

Every year, 1-2 questions come directly from projectile motion. The key is understanding that horizontal and vertical motion are independent — gravity only affects the vertical component.

Key formulas

Projectile Motion Formulas

Range

R = u²sin2θ/g

Maximum at θ = 45°

Max Height

H = u²sin²θ/2g

Maximum at θ = 90°

Time of Flight

T = 2u·sinθ/g

Independent of horizontal motion

Horizontal Velocity

vx = u·cosθ (constant)

Gravity doesn't affect vx

Step-by-step problem solving

How to solve projectile motion problems in JEE

  1. Resolve initial velocity — v₀ₓ = u cos θ, v₀ᵧ = u sin θ. Horizontal and vertical components are independent.
  2. Choose axis/sign convention — upward = +, rightward = +. Gravity g = -9.8 m/s² in vertical direction.
  3. Apply kinematic equations — x = v₀ₓt, y = v₀ᵧt + ½gt², vᵧ = v₀ᵧ + gt. Use time t consistently.
  4. For max range — set θ = 45° — R = u²sin2θ/g is max when sin2θ = 1, so 2θ = 90°, θ = 45°.
  5. Check if launched from height — use y = v₀ᵧt - ½gt² and solve for t when y = -h.
Common JEE mistakes

What students get wrong

❌ Forgetting vx is constant

Horizontal velocity never changes (no air resistance). Only vy changes due to gravity.

❌ Using 45° for max height

45° gives max RANGE. 90° gives max HEIGHT. These are different!

❌ Mixing up sin and cos

Range uses sin2θ. Height uses sin²θ. Time uses sinθ. One letter difference changes everything.

❌ Ignoring the sign of g

g is negative when the projectile moves up, positive when it comes down. Set up your sign convention first.

FAQs

Projectile Motion Questions

Why is 45° the angle for maximum range?

Range R = u²sin2θ/g. sin2θ is maximum when 2θ = 90°, so θ = 45°. At this angle, the horizontal and vertical components of velocity are perfectly balanced.

Does mass affect projectile motion?

No! Without air resistance, mass doesn't appear in any projectile formula. A feather and a cannonball follow the same path in a vacuum.

What if the projectile is launched from a height?

Then you can't use the simple range formula. You need to solve the vertical equation s = ut + ½at² with the initial height, then find when y = 0.

Is horizontal velocity really constant?

Yes, in ideal projectile motion (no air resistance). Gravity acts only vertically, so vx = u·cosθ stays the same throughout the flight.

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